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Parser: Properly represent parsePar in grammar

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Adam Strzelecki 2015-06-02 21:51:41 +02:00
commit 2f5ed17cfe
1 changed files with 6 additions and 4 deletions
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compiler/parser.nim
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@ -499,9 +499,11 @@ proc parsePar(p: var TParser): PNode =
#| parKeyw = 'discard' | 'include' | 'if' | 'while' | 'case' | 'try' #| parKeyw = 'discard' | 'include' | 'if' | 'while' | 'case' | 'try'
#| | 'finally' | 'except' | 'for' | 'block' | 'const' | 'let' #| | 'finally' | 'except' | 'for' | 'block' | 'const' | 'let'
#| | 'when' | 'var' | 'mixin' #| | 'when' | 'var' | 'mixin'
#| par = '(' optInd (&parKeyw complexOrSimpleStmt ^+ ';' #| par = '(' optInd
#| | simpleExpr ('=' expr (';' complexOrSimpleStmt ^+ ';' )? )? #| ( &parKeyw complexOrSimpleStmt ^+ ';'
#| | (':' expr)? (',' (exprColonEqExpr comma?)*)? )? #| | ';' complexOrSimpleStmt ^+ ';'
#| | simpleExpr ( ('=' expr (';' complexOrSimpleStmt ^+ ';' )? )
#| | (':' expr (',' exprColonEqExpr ^+ ',' )? ) ) )
#| optPar ')' #| optPar ')'
# #
# unfortunately it's ambiguous: (expr: expr) vs (exprStmt); however a # unfortunately it's ambiguous: (expr: expr) vs (exprStmt); however a