Add day8 problem + solution
This commit is contained in:
Joey Yakimowich-Payne
parent
084a6dc1e8
commit
33c5b2c829
4 changed files with 450 additions and 0 deletions
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day8/input.txt
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day8/input.txt
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bgeacd dbfag bcadegf agdce dgfbce bgc bdgca aedcgf bc abec | gcdfbe cbea bc gbc
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bdeag gdbaec cd dgc abcfg ebcd dgfabe cdfeag cgadb bdagfce | becd acfgde bgcaed eadgbc
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acbfg bcf ebacg fb fcbgea cbdfge cgeabd agcfd aebf bdaefgc | fbcdeg cfb ebgca bf
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bfcde dfgb gecbdf fdc fdcega fd ebdca gfcaedb gcfbe cbagef | dbfec gbfd bcdfe dfc
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dbgeaf bad acdfbe ab agbdf bgcdf fdgae fcgbdea fgecda egab | ba dab abd gbae
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feagcb cdfagb egda bdg dg fdcagbe ebcga bedfc bgecd dbcgea | eafgbc bcdfage dg egad
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bacfedg afbgc dbcgaf afgecd acd bfagce bgda ad adfbc ecbdf | dca dca abdg dcbef
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eagfb efcdba faceg gfdce cea afbcegd ac afdegb gafcbe gbac | fegcd geafc edbcaf bcag
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cfb bgfce ebgdf fc gdfeab acdbfeg cgeab ecfd badfcg ebcfgd | ecgab eagcb efbacdg fc
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adfec ebdcgf bfced bec fagcdeb gbcd cb fbgde deagbf afecgb | bce cb fdgeb bc
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bgfaec dcfga ed acedgfb fdebgc dec fdeb gedcba gfced cebfg | cde agcbde gfaecb cde
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bgefc cfgbea dfgaecb dg dbcg dcefa dfbegc dgfce afgedb fgd | cfged gdf fbgdea gafecb
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fcbade dagbe gacb gaedfc bdaecfg bgfde dbaec baegcd ga dga | ag gad gcab ga
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cfgdeb cbfade fac badfc ca gafdce gfdebac bfadg fbdce aceb | ebdcf deagfc ac ebfcd
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debfcg fgde cfaedgb ecbag cbeadf gf gbf fdceb fcebg dfagbc | gbfec gf agbce bfcagd
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fdcebag cbeagd gafed dfbgc cgedfa beg be edgafb edbfg eabf | gbcfd acgefd cfdageb afged
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bgad efdbcg aecfdgb fgebca ga cgade acbedg adfce aeg cgdeb | gdecfb fgdceb adceg ga
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acefd efdb cgabfe be fegcbda gbacd cagefd eab acebfd acbed | be debf feacgb becad
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edbcag dgefcab ce fgdcb eafc afgceb gfbae cbe degafb bfgce | fcgbd ec dbaegc efgdba
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bfcdge gfcbda aegfcdb dg cdgbe dbfce dgb fged cdefba caebg | dbg bgd gdfe dg
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bfeadc dbfcgea bgdaf decfg efdabg cgba fbdagc ca fca gdcfa | cafdg gacb bdfeag ac
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edbcfg cdgfae gedaf egcfd beagfc fga bcfdgae cgda debfa ag | defgc efabgc fcegadb fegda
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gafcb fcgadb gdca gbadf ad fbegd befcag fda ebgdcaf fbaecd | agcbf dbafcg dgafb abgfcd
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cga gafce gecbfda dbacgf defac febcg cfbdeg afegcb bgae ga | cdbgef ebdagcf caefg geba
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gfebcda ab dfabg abcfgd gdbfc abgc becgdf bcedfa adfge fab | abf fab ba agbc
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fagce ceabfgd cdea cbfaeg dgafce egcdf bfaegd gbcdf fde ed | de aedgbf fecagd fcebga
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fcbad fe afge ebagd fde fbdegac fgbced fdgeba fabed edcgba | debga bdgae bafdc efag
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adbfg ba dbcfga abgdecf gfedb agfdc gcdeaf adfebc bda bacg | befdac ebdafc abd gdbafce
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begfd dgfbac dgbac ce bedgac dafceg dgbce ecfdgab ceg ecab | gadfcb gefdb gdeafcb fgcdab
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dcfagbe dgbefa gdbcea faebgc fade efabg dge cfdbg fbgde ed | de efbacg dfea dfea
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dcfeag bgefcad dcgfe afedb cb bfgaec dcgb bec fcdbe gbecdf | bec agfebc ecb edfba
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acdbgfe ebcag fgc feagcb bafc gfceb fc gfadce gcbead dbgef | bceagd fcab gfdceba cfebg
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bdegf abgefd fgba dgceab dabcef badfegc egb fadeb gb fdgce | gafb efdba gb dbfage
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bfdca cfgb agdfec caf bgcfda becad gbdaf fc ebgfcad bagedf | gefdab cebad cf bgfc
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dfbcge bedgaf bgefd cgebda efcb gcfad degfbca bgc fcdbg cb | ecbadg gbfdc bgdfe fcbe
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dfeagc bfacge abfc fcegb bdecg bef acfeg bf bcgaedf gedfba | bf ebf fb cfadegb
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fbgdc fcbgead egaf acebgd gacdf fad gdaec bfecad fa gcedaf | eafdgc fda degacf geadbc
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fcdea gcdbaf cgedbf bd bgde cdb acfgeb efcbg fdecb fedbacg | aebgcf febdc dcb bgdefc
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bfdeg dbcefa bdaegf cegdf agdb fdaeb bge gb beacfg edbcafg | gefdb edcfg acbgef egb
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afgedbc caebg gef fbec egcdba dfgabe gafcd bfacge agcfe ef | fge eafbdg cgbae cgaefb
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cbagfed dceba efgcb bcafde gacedb fdca caebf egfabd fa aef | adegbc cbgfade adcf deabc
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gcbd bcegad eagdb fedabc acebdgf gcbea gaebdf gacef bc bce | dbaegc cgfea bcdg ebc
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cbfdeag agfbce cagef cbdefg gb gefab gcedfa gfb fdeba abcg | bfg afegb gbf cgab
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dea fadgbec dcabe abcdeg cfbad gdec agecb gdefab fbgaec de | dbgfae cdfegab dbgcae beadcg
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gabcd aebdgc gcaefbd edac gbfad cebag efcbga dc dcegbf cdb | cbdag agebc afcebg faegcb
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gacdbe cdabefg fecgab fe gef cbdgef dcfe gdfeb cbegd dagfb | egf fe efg decgb
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cbfea bcgf adcfe ecbgad bf gfebad feb bfagce afdcgbe abgce | cadef bcfg bf dbfcage
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fabeg cfeab ebgfcad ebfgad eg edag dfbag feg defcbg fbdcga | efbga fdcegb gbafd gdbecf
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cdgfba bga geabdc dacge beadf ebgc agcfde bg gbacdef bgead | cebg fbdae gbec dagfce
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fbgdace deafcb ead caedg da decgba aefcg bedcg gdbecf badg | ebfdcg gbad ecagbd egdcb
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faebg fg gfca eafbd cgbaef baecdfg cedbgf eabcg efg dgceba | edcgfab feg gf efg
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adbec dbcaf ecga dea eabfdg cdbge bafdcge bgdcae ae fedcgb | ead cabdgfe agce egcfbd
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gdcef agfb bfgade cebdaf debcagf dbafe egbfd cdageb geb bg | egadbc gcdfe afgb egb
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gfcbe cgfabe cdagb debgcf de bdef gde dbgcefa dfecag edcgb | fcegb fdcagbe fcbge edgcbf
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gaedcf cfedba dgacb cgbeaf fbge ecafg bfdgace gfacb bfa bf | gcadb decafg adgfec baf
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eadg gfadbc eagbcd agbcd cea bdafgce cdfaeb ae gcfbe geacb | ea cdeagb debgacf egad
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afecgbd eafd adbgf egfdbc cbeag bgfead egafb fe gdacbf efg | egcab gef dbagfe abgecdf
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gafbde geab efdcab badef cfdeg gfa egcdafb fdeag ag abfcdg | fcgde ebfad bgae ebdfa
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adbef adbcfg fbgace eac ec egcb afcgb cfeab faedgc dgfebca | gbadfc eca ecgb cgbe
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fb efadcb fab gbfeca gfcab baecgd fadgc gfedabc gbef cgaeb | beagdc cabfg bacge gbfe
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dfabcg bcdg dagbf aegcbfd db fbd gcbaf gefad feabdc gcbeaf | fagdb bacfdg gabdfc dcgb
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ecagbdf dgfac cefag geacdb dcefgb df bdcgfa afbd abdcg fcd | dfc defbcg df afbd
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bfadc bcgad acegd bg ceagdfb bag cdaefb fcgb cgadfb gdebfa | cfbadge efbdcag fcdab dcbaf
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bdcefa gc cgb egdc ecdbf cfdgba agfbe dfgebc cdgaefb gbfce | cbegf begfc ebcdgf fabge
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caedgf egf dcebg cfbeg edgafbc bgdf ebdfcg eacdgb gf eafbc | bgfd efgcb fg afbcegd
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gbfae cdabfe degc edb cbdfg ed ebdgf dbfgce baecgdf agdfcb | adcefb ed de cfbgde
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fdbcge defabcg fgead befda gacedf ag gdca gea cgeafb fdegc | ga fecgd ga dfegc
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ed efcgab edacg adcgbe acgefdb deba fcbedg agfdc bgace ecd | afdcg bceag de gcdeab
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facdbe dagec bfcea bcd dfcgbe cbdae bd abdf bgcefda cbegaf | dcb aecbd befac ecfdab
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fa fea gafc gfebd dcabge dfbaegc gacfeb abgfe baefcd bcgea | befdg gecfab cafebg agceb
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cebad ebdgca bd fbedacg gaefdc gadce becaf gebd cfbagd cbd | dcgfea abcgdf cdb bd
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cfbgdae cgfdb cabgef df bdfa bgfac gcadef dfc fcgadb egbdc | df faedgc dcegb dcgbf
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cbfg gecfa adfbge gfbcdea eabfcd fg bgfeca acedg fga bafce | efbgac dcfabe cebafd decag
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gdcbef dcfage acgde fgbea gedbac bc bgace gdaefbc ecb dacb | abdc bfgea ebfgcd adcbge
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gafe cfbad aedcfbg adbgce cebgfa agcbe gf gbedcf gcabf gcf | bcega begcfa gafbc feagbcd
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cabefg ce ecfb dcebagf gface afged fbcga afcdbg eca cegdab | aec ec gafecdb bdgcaf
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bgdcae cedga bdgaecf cd afegd dbac dgc efagcb gefdcb cegba | efbgca bdecgaf caegbd dgc
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aebgd cfageb ecdagb beagc bcfdeag dfgab de ebfdcg dge adec | ed gfebca de fdcegab
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ebcdagf fcga gfbaed gf dgfaec ecfad adcbef gdcef gbdce feg | dfcae fge feg fbegcda
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fba cegadbf fa deaf deabg fedbag dgcbf agebdc gafbd bgfeac | bfa bfa fgcbead fbedgca
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cdgef dgbcaf gadcb edacgb agfdc adbfce gaebcfd fa abgf dfa | gbfdac acfgd gfcda fegdc
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dcagbf cfda fcdbge cf bafcg bdgace adbcg agebf bcgedaf gcf | dcbegf bgdac gafcbd cgbda
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degfac eafcb dfacg gbcaedf gb dfbg afbgc bag bcgeda gfbdac | dgcefa dgbf bga fcgad
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deg fgdb feabd dg gefac fedbca eacgfbd ebacgd abedgf dfaeg | egfda gadfe edg dfbae
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degf fcagde cgdebaf cgf cafgd gf fadce cgfeba gcbda fcaebd | cdbag bdcag egdf dacgb
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fdgb bagfdc dbcaf fb abdceg fba fbeacgd geafcb afdce bgadc | bf fba dbafc gadcb
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aegdb fdagceb bafce fad dgabfe df cagbed fdeg aefdb gfacdb | becgad adfbe afd badfe
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fdbg gfabc fcabd fd abcegf gadbcfe ebcad dcf dcfbga fagdec | bagcfe gfacbe fd cagebf
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cgfd egdca fdaceb abegd egabcf eacfg ecbfgda dca fdcage dc | egcaf ecbdgfa abcfed dcgf
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efdgba cgfeda ac gabecdf efagd adcef fac cefbd gcea dagbfc | afebcdg ca bcfed ca
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acbfeg bg fecbgd fgdeac acebgfd gbe bagc afecg fbead begfa | agcbdfe bg fegba badegfc
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eadbgc edfba bfecdg acfb egfad ba bea dfceb dcaebf beagdcf | ab eafbd abe adcfgbe
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fbega afdce gd agcebf becgad bgdeaf fbgd gde ebgfdca efgad | cegdab cefbga fbgd geadf
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cag agfce gfacde gbcdaf ag gead fbgec cdefa bdafcge bdefac | cfead gca adge bdagcf
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dc cebfa egacfdb dcf edbfc cbdgfa fdebg gefdba cged fdecbg | dcf eafbc bgacdf dc
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edbfg fdacge dcgae baegcd bacfgd ecaf geabdfc ecdfg fgc cf | defcag dbfgca ebfdcga cebdga
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fdgec gd gfd efcbd fdagbc bedg fabedgc gaefc becadf fdbecg | gacfbd fbdcag dgbe edcbf
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fec dgebf fbdc efbdcga afegcd befagd fdcgeb fc egcfb cgeab | bdefgc dfegba degabfc fc
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cdb gdfc dc cbdega eadbf egfacb gfcebad cgbfda acbdf bagfc | dgaecb cd bafed dcb
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dcbga ag cgdaef fgbdeac daebc fbag cag fgcdb ebfgcd fbcgad | ag faegcdb acgdfe dfgcba
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dabef fa ebacfd dfa bdfec fbgdca cbfegd dbcegaf bgaed efca | gdaeb afd eadbf fa
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bed dgab gfced afgbedc dfbge geafb efadbc febdga cafgeb db | fgeba gdba aegfcb gfecd
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da gbacf becdaf ebcfgad ecad cgfbde fedgab dbfca fecbd abd | ad egbfdc bad fcbag
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efc bgfceda dfbcag ecbg efagd acbgf fbagec aecfg ce bfeacd | egfac ec afecgb fbeacgd
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aedfbc gaced fabg ab bdgfc gefbcd adb gdbac acdegbf gcfbad | ba bcgdf ebfcda bafegcd
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cdgfb abegdc fgeacbd feba ecafgd gebfda ef efd dbfeg bdeag | dfe egfdb agefdb bedga
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cagfb ef fcdgae cfe cgafdb bcedg fbdgcae bcegf feba acgfeb | gefdac egfacd cgebd feadbgc
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bfgedca cabfgd gbac ebdfa ag abgfd dga egfdac bdcgf gbcefd | cafged bgadf ceafgd ag
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gebda bc eagdbfc ebdcg cdbgfa cgb ecdgfa cefb gfdec fbgecd | dfgbac cebf dgbecf fcbgade
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dfbcag dafgc bfd fdgcae gebda ecafbd gfadb gfcb fb dacgbef | gbdfa dagcf dagfc fbaced
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cd dfebg fcdgb cadb gdeacf eafcbgd gfceab cdg abgcf dgbfca | dc fbadcg cd adbc
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becafd dbfa feb fb abgcef adgefc cefda bgced edcfb bedgfac | fcdabe bf feb dfab
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gbadfe fdcage acgef fed ed decg abgfce adcef gebfadc fabcd | ecdg afbcd afdgce fde
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fcaedb dgbca fdcg efgbdca fbgca befag caf bagfdc dbaegc fc | fca gfacb bgceda fc
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cabed fbed fd cfd fagecd bfdca bfcdaeg acfgb bedcaf dcgbea | aebfdc ebfd bdcaf fcdgea
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agdbfc fagbc fgdc dgacebf bcgaef fda ceabd bdfca fbgead fd | fda fdcegab bgafc edbafg
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cbgfa bfdgea bfdgc ga fga aecbdf gcae egbcaf bcfgdea cefab | ga fcabe fgbdc gfbac
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cgafe cbagdfe afbce afegdb efgda gebcda gc gdcf cag eagdcf | befca gafed eadbcg gca
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agfce edgcba egbac gcbf fagbde gdacebf agf cdaef gbeacf gf | fecag bgace gdfbaec bgcfdea
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be gaeb gdeaf fcdab cbegfd fgeacd efdab fbe cgebfda dagebf | feb dfgacbe faedcg egfbad
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dfcba cgfdbae gda afedcb bgca bagcfd ga gbdef eadcfg bgafd | bgfad gfebd ag efabdc
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edgafb dgef agbedc gf abfgec fcdgeba adfbg abdeg fga cfbda | dafecbg badfg bcagdef fag
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fgc cgfbe ebgaf cbfa cgedbfa cf bgced gecfab defbag fgdcae | gfc cgf gbdfea fcg
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cga bcadfge aefdgc edgca dafc gdafbe aefcbg agefd ca cdegb | debcg faecgb cga gac
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dbcaf gcadebf eafcgb dbcefa gbdf cbfdga bcg adbcg gb edacg | afecbg cbg bfcad cabfdg
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fd dgaeb def fgecb fdebac feadbg eabdgc dfgeb becfdga gafd | fbgce egadb bdgea fagd
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cedbgf dbcgf febcad dgeafcb efcagd bfge cfg bdcga dbcfe fg | gcf cbgda gcf cadfegb
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gfabc agc degbaf fgaecb gaefb ca cefa bedgac fedgbca gcfbd | begdca gbdcf cag eacf
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ebfa be fgbcd afcegd cbe febcd faced egfdcba dbface aecbgd | ceb ceb cbfadeg feab
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gbfad cdeabgf bdeag de afcdge ade cdbe ebacg geafbc adcbeg | cbdefga gaceb ed bdce
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fcedbag adfeg fadebg cbgda fdeb fba bf egdcfa gfadb cfbgae | bf fegad gabdf dgcba
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abde debfgca acfegd ae fgcbe dabgc gbadfc cgeba cgeabd aeg | eag bcfgdae gfebc aegbc
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afdeb caegfd dcgb bcafge egabfcd fgd cgfbad dgbaf fcgab gd | aebdfgc bcdg agfebcd fdabg
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ecbafg acdbfe bfge cfaeb cedga cfega dafgbc afg gf bcfgaed | cbdfga fg efagc geacf
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ecafbg adgfecb fdeac agbd cbgdf cfgbda agf ag bedcgf agcdf | ga ga fag cfdbg
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gcdbe cbadefg cdf dfea df gfaebc facbed cfbae bagcdf ebfdc | afde aecfb cbfdea caedfgb
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gcfb beafgd fdg deagc cfbed fg gacdfeb gdcbef fcebad gedfc | cdbef dgf dfg bcfdgea
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dgebfac eacdbf bdc abgdc adbeg cadgf cbfg cegfad gcbfda cb | cafdeg fdacge facgd bcd
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cdeag becf fgdbac fc gbfaced edgfc dgebaf gbfdec edgfb cgf | gafdeb daegc bcdfge egdfab
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aegd cgd abfcd cabgde fdegbc dg ecagb dagfbec cbegfa badcg | ecagbfd debcgf agde bacfd
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cfdge gb abfed bdg cbge gfedb bgfcdae cbdagf begcdf fcdega | cgbe bgd cfbgda fcedg
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egdfca eafdcb ecdag dbgfac gefa ag bcfadge agc gcbed dacfe | ebafcdg acefd fdcae agc
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afbgec edgb dafeg fegab agfdc de eda fbdgcea dfaecb fdegab | ead aed cfebad bceafg
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dbgc gbeaf acfebd agd afecbgd fabdc ceagfd gbfda cbfagd dg | gcdb efdacb gfdbca gbdc
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afcedg gbad dgecb gcefb acdbeg dg abedc dcg dabcef gbdcfea | cgdeaf beacfd cbade cgdbe
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ea egfdba dgceaf daec cfgbe eag befgdac fegca cadfg fabgdc | fgceb adfgc abcfgde gaefcd
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agdebfc dbgca egb egfd abfde agdfbe fcbade fgeabc dgbea ge | bdgca debaf aedgb fegacb
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efcbd ecgd fbecgd adgbf egacbf bfcgdae ebg fdebg ge dcebfa | gfceba cbdfeg eg fgceadb
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dc befgac cdb aced gcbfead dcgefb adfbg acgbd cabeg eacdbg | edcabg bdc dgcaeb acbgefd
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afgbc dbaf ebcfg ba ecfgdab adcfg bca fcaegd cgabdf gcabed | bfgce egadbc cbgaf acdbefg
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cagbd adg cegafd acfgebd bdaec gbfd gd gbafdc bgacf faegcb | gebacf dg gda agdbc
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||||||
|
bc cdgba adfcg ebadg cfbdae ebfgad dgbfcea cba bgec gbdace | bc cb dafgeb cab
|
||||||
|
gae bfegc edfac gdca ga begdaf cgeaf edafcg bafedc cfbedga | adfcge ecdfag fabcde aecfdb
|
||||||
|
cdfge db eabcf fdb bade cbfed cbfdaeg gfbdca dcbefa cgfabe | dbf cbagdef db abed
|
||||||
|
efa facg beadcg gacfde cbfed dcefbag adceg fa gedbfa cfdea | agecd gcbaed afcde eacdg
|
||||||
|
dbgca dfbeg fcg adbcgf bafgce fdca cgbdf gabdcfe dbecga cf | gacefb cabdg dfca fcg
|
||||||
|
dbfcae gc decg ebadc cga abegf cbfaegd cbage gabfcd agdebc | edbcga gebca cebda baegdc
|
||||||
|
becagd gefcdba bgaef gfadcb fgd fadc bdacg dfagb fd ecdbgf | dgf fgaeb cdaf fd
|
||||||
|
egfcab dcfgea caebg ag cbeafd edfabgc gfba bcdeg acg ecafb | cfbaeg gac acgfed eabcg
|
||||||
|
gbc gfbad fgbac beadgf cg fbeac gdfbce dbgcaf bgcfead cgda | gacd edfgbc cbg gafbed
|
||||||
|
fgdba begcad fg gfd fdacb debfag egdba adfcbge fgbedc afeg | afdbg bdaeg badfg eagcdb
|
||||||
|
cefgdb fdecga beafg agd acbd badge cgfdeba cebdg ad dacbeg | cabd cedafg cfedag fgaeb
|
||||||
|
fgc cdefb beafcg dcfbg adbgfe cgad acefbgd adbfg cg afdgcb | fegcdab bagfecd gfdcb gcad
|
||||||
|
cbagfe cbedgaf bfgde cfdeab gfeba df fgda dcbeg afebgd bfd | fd adfg ebgcd fcabge
|
||||||
|
ebgaf ad ebacgd adfgb cadf abfdcg badgecf cdgfb bad ebcgfd | bdegcfa cfda fbaeg gbcfad
|
||||||
|
adfcg dabecg gaebfcd ecfbag bgacf gdc bgdf cbfagd eadcf gd | dg cfgab fcgab agbfce
|
||||||
|
ecfgdb dcgbfa fdage ecda ad ebfag dfa bfadecg fadecg cegfd | ad dgefc cdae bgdecf
|
||||||
|
agcfed eabdfcg aec ce gacbd gadec geafd cefd bagdef cgafbe | ce aefbdgc egcbfa gaecfd
|
||||||
|
gdace fe bdgafc efa dbafecg fgeb bdafce beadfg egdfa dgfab | ecgda fe fbgad fedabg
|
||||||
|
fg bdgcefa gabed defga fbeacd bdcafg cfeg gfd edcfga fdeac | agfde fg fcbade dfgea
|
||||||
|
dcgfbe egdfc gcbd dc geafd becdaf gcabfe cde efbcg gedbfca | dc fgead dgcef gdcb
|
||||||
|
gdefa efadbc cfdebga adfebg eaf ebag ea adfbg cfdeg acgfdb | fgdbaec cabgfed dgafe efa
|
||||||
|
fecb fcegbda dgeaf eagdbc eb dbegfc cfgbad beg gbedf fbgdc | bcef dfegb gbdfca dgcbafe
|
||||||
|
befg bafde afgdc degfa cdeafbg edafbc dge eagcdb gdbafe eg | dge efbad becgda aegdbf
|
||||||
|
ac adfgc cedfg bedgac cda ecfagd degbcf fecabdg afec badfg | gdfab dcgaf fgced cegafdb
|
||||||
|
cda badcg edcgb geca ca bdaegc dbfaec decgbf agfbd ecdgfab | ac bdfag ca edgbfc
|
||||||
|
fgac febgca fg ebacf bgfecd gfb gbcfdea badeg bfage bedfca | gbefcda fg bdfceg gcfa
|
||||||
|
bcgfade ce fcge dbgcfa cdafe badgec acgfd gceadf befad edc | bagcfed ecfda fcgad dce
|
||||||
|
ebacfg efbad fcbaedg age dfagc adefg cdge eacgfd ge dgfabc | geabfc cdfagb eafdgc gae
|
||||||
|
abd cgbde da gdcaeb cagd baecd faceb afdebg ceagbdf egfdbc | agdc gadc gedbcaf bcafe
|
||||||
|
eg bdfgec dcfbe facebg efg gabcedf dcgfe cedfab afgcd debg | ecgdf cgefbd cdgef feg
|
||||||
|
eagf efbdgc dga dcefg cdgfea bcdea cdgfab ga gdeafbc ecdga | gcdae aedgc ga ecdab
|
||||||
|
ga cbedg eacfdg acg eabdcf ebafgc adgf cfeda egadc dacefbg | dfag fbcage bafgce acgde
|
||||||
|
gfea cgdfeb efabc agfedcb gfc afegbc gf cdfbae abgfc dcbag | caebdf beafcd caebgf baecf
|
||||||
|
efd gefa gedcab dcfab cfdea ecdgafb fbdceg egdfac ef agcde | gafcde ef aefg cadfb
|
||||||
|
bafecdg deafbg fadeg bga deagbc gebfc bafd efbag ba dcgeaf | gedaf ba dgbaecf ba
|
||||||
|
ag dga geabfd becadf gbaecd abecd aceg bagcd cfgdb cebdgaf | egfbad aegbcfd cgae dacbe
|
||||||
|
bcdgeaf gbfda afcged gfebd fa dgfcbe efab agf bdcga dafgbe | gafedb efbgda ecagfd fgdbe
|
||||||
|
degafc feba fgbcde bafegcd bge adegb be dfega efadgb cgbda | dbegcfa acbgd faeb acefdg
|
||||||
|
gdcfeb ea fceab fgbca adfbeg eadc cdebafg cebdf aef fecabd | cefba fae dcea efa
|
||||||
|
agfde dbega fg dcfg ecadfb cegbaf adfec adecgf adebgcf agf | dgfc gcfade afbecg dcfage
|
||||||
|
fbade caebg becadf fgdb gfa dafgbec fg afgeb fbeagd gaedfc | eacfbd bgeafcd fg efbad
|
||||||
|
gbdacf aefd ed geadcf cegfd fcgeadb dbeacg cadgf ecgfb dge | gbacfd beacgd ecgadf cgfbda
|
||||||
|
adebgf gdf cefgdba fd gcfba efad dbgeca agebd afgbd fdegbc | deaf gfbdea df dbaeg
|
||||||
|
adgbf cbfg fagde facebgd gbd acdbf badegc baecdf gbfdac gb | bdagfc gcfabed fdcab cdfab
|
||||||
|
dbgace cbdfg ab dfagb abef abgfde gaedf bad ecdafg gcdbeaf | ba cbaedg ba dfbga
|
||||||
|
bgcade acbedgf gbef cef cdbfa ef cbefd afgecd bgdce fbcgde | ef ef fce dgecfba
|
||||||
|
gbfced abegc cde acbde fcgaeb cd gebacd agcd gfabdec abdef | gdca gacd dcbae bdegafc
|
||||||
|
gb facdb fedcab fgb gadebf aegfc dgcb cabdgf gbcfa eafcgdb | fegbad adfcb dafgbe fdcba
|
||||||
|
gfbaed fcabde gdbfc bdeafgc dgb agfcdb cgda fcdab gfbec gd | becadf facdeb dg agbdcf
|
||||||
28
day8/p1.nim
Normal file
28
day8/p1.nim
Normal file
|
|
@ -0,0 +1,28 @@
|
||||||
|
import os
|
||||||
|
import std/strutils
|
||||||
|
|
||||||
|
type
|
||||||
|
Segment = enum
|
||||||
|
One = 2
|
||||||
|
Seven = 3
|
||||||
|
Four = 4
|
||||||
|
Eight = 7
|
||||||
|
|
||||||
|
proc main() =
|
||||||
|
let fileName = paramStr(1)
|
||||||
|
|
||||||
|
# store count for 1, 4, 7, 8
|
||||||
|
var count = 0
|
||||||
|
|
||||||
|
for line in fileName.lines:
|
||||||
|
let display = line.split(" | ")[1].strip()
|
||||||
|
let digits = display.splitWhitespace()
|
||||||
|
|
||||||
|
for digit in digits:
|
||||||
|
case len(digit).Segment:
|
||||||
|
of One, Four, Seven, Eight:
|
||||||
|
count += 1
|
||||||
|
|
||||||
|
echo "Count of 1, 4, 7, 8: ", count
|
||||||
|
|
||||||
|
main()
|
||||||
104
day8/p2.nim
Normal file
104
day8/p2.nim
Normal file
|
|
@ -0,0 +1,104 @@
|
||||||
|
import os, sets, math
|
||||||
|
import std/[strutils, sequtils]
|
||||||
|
|
||||||
|
type
|
||||||
|
Digit = enum
|
||||||
|
One = 2
|
||||||
|
Seven = 3
|
||||||
|
Four = 4
|
||||||
|
TwoThreeFive = 5
|
||||||
|
ZeroSixNine = 6
|
||||||
|
Eight = 7
|
||||||
|
|
||||||
|
proc main() =
|
||||||
|
let fileName = paramStr(1)
|
||||||
|
|
||||||
|
# The main idea here is to use process of elimination to find each number
|
||||||
|
# uniquely. To do this, we can use hashsets to eliminate or isolate numbers
|
||||||
|
# that we don't know.
|
||||||
|
|
||||||
|
var sum = 0
|
||||||
|
|
||||||
|
for line in fileName.lines:
|
||||||
|
let
|
||||||
|
lineSplit = line.split(" | ")
|
||||||
|
allDigits = lineSplit[0].strip().splitWhitespace()
|
||||||
|
displayDigits = lineSplit[1].strip().splitWhitespace()
|
||||||
|
|
||||||
|
var
|
||||||
|
oneDigit: HashSet[char]
|
||||||
|
fourDigit: HashSet[char]
|
||||||
|
sevenDigit: HashSet[char]
|
||||||
|
eightDigit: HashSet[char]
|
||||||
|
twoThreeFiveDigits = newSeqOfCap[HashSet[char]](3)
|
||||||
|
zeroSixNineDigits = newSeqOfCap[HashSet[char]](3)
|
||||||
|
|
||||||
|
for digit in allDigits:
|
||||||
|
case len(digit).Digit:
|
||||||
|
of One:
|
||||||
|
oneDigit.incl toHashSet(digit)
|
||||||
|
of Four:
|
||||||
|
fourDigit.incl toHashSet(digit)
|
||||||
|
of Seven:
|
||||||
|
sevenDigit.incl toHashSet(digit)
|
||||||
|
of Eight:
|
||||||
|
eightDigit.incl toHashSet(digit)
|
||||||
|
of TwoThreeFive:
|
||||||
|
twoThreeFiveDigits.add toHashSet(digit)
|
||||||
|
of ZeroSixNine:
|
||||||
|
zeroSixNineDigits.add toHashSet(digit)
|
||||||
|
|
||||||
|
# this section is pretty inefficient, but reduces code complexity. Since
|
||||||
|
# the seqs are only length 3, iterating over them multiple times is fine.
|
||||||
|
#
|
||||||
|
# we isolate the numbers based on process of elimination to uniquely identify
|
||||||
|
# each number
|
||||||
|
let
|
||||||
|
twoDigit = twoThreeFiveDigits.filterIt((it - fourDigit).len == 3)[0]
|
||||||
|
threeDigit = twoThreeFiveDigits.filterIt((it - oneDigit).len == 3)[0]
|
||||||
|
fiveDigit = twoThreeFiveDigits.filterIt((it - twoDigit).len == 2)[0]
|
||||||
|
|
||||||
|
lowerLeftSegment = twoDigit - threeDigit
|
||||||
|
upperLeftSegment = fourDigit - threeDigit
|
||||||
|
middleSegment = (fourDigit - oneDigit) - upperLeftSegment
|
||||||
|
upperRightSegment = (twoDigit - fiveDigit) - lowerLeftSegment
|
||||||
|
|
||||||
|
zeroDigit = zeroSixNineDigits.filterIt((it - middleSegment).len == 6)[0]
|
||||||
|
sixDigit = zeroSixNineDigits.filterIt((it - upperRightSegment).len == 6)[0]
|
||||||
|
nineDigit = zeroSixNineDigits.filterIt((it - lowerLeftSegment).len == 6)[0]
|
||||||
|
|
||||||
|
var localSum = 0
|
||||||
|
|
||||||
|
for i in 0 ..< displayDigits.len:
|
||||||
|
let displayDigit = toHashSet(displayDigits[i])
|
||||||
|
var digit: uint8
|
||||||
|
|
||||||
|
# there's probably a better way to do this
|
||||||
|
if displayDigit == zeroDigit:
|
||||||
|
digit = 0
|
||||||
|
if displayDigit == oneDigit:
|
||||||
|
digit = 1
|
||||||
|
elif displayDigit == twoDigit:
|
||||||
|
digit = 2
|
||||||
|
elif displayDigit == threeDigit:
|
||||||
|
digit = 3
|
||||||
|
elif displayDigit == fourDigit:
|
||||||
|
digit = 4
|
||||||
|
elif displayDigit == fiveDigit:
|
||||||
|
digit = 5
|
||||||
|
elif displayDigit == sixDigit:
|
||||||
|
digit = 6
|
||||||
|
elif displayDigit == sevenDigit:
|
||||||
|
digit = 7
|
||||||
|
elif displayDigit == eightDigit:
|
||||||
|
digit = 8
|
||||||
|
elif displayDigit == nineDigit:
|
||||||
|
digit = 9
|
||||||
|
|
||||||
|
localSum += (digit.float * math.pow(10.0, (3 - i).float)).int
|
||||||
|
|
||||||
|
sum += localSum
|
||||||
|
|
||||||
|
echo "Sum of digits: ", sum
|
||||||
|
|
||||||
|
main()
|
||||||
118
day8/prob.md
Normal file
118
day8/prob.md
Normal file
|
|
@ -0,0 +1,118 @@
|
||||||
|
--- Day 8: Seven Segment Search ---
|
||||||
|
You barely reach the safety of the cave when the whale smashes into the cave mouth, collapsing it. Sensors indicate another exit to this cave at a much greater depth, so you have no choice but to press on.
|
||||||
|
|
||||||
|
As your submarine slowly makes its way through the cave system, you notice that the four-digit seven-segment displays in your submarine are malfunctioning; they must have been damaged during the escape. You'll be in a lot of trouble without them, so you'd better figure out what's wrong.
|
||||||
|
|
||||||
|
Each digit of a seven-segment display is rendered by turning on or off any of seven segments named a through g:
|
||||||
|
|
||||||
|
0: 1: 2: 3: 4:
|
||||||
|
aaaa .... aaaa aaaa ....
|
||||||
|
b c . c . c . c b c
|
||||||
|
b c . c . c . c b c
|
||||||
|
.... .... dddd dddd dddd
|
||||||
|
e f . f e . . f . f
|
||||||
|
e f . f e . . f . f
|
||||||
|
gggg .... gggg gggg ....
|
||||||
|
|
||||||
|
5: 6: 7: 8: 9:
|
||||||
|
aaaa aaaa aaaa aaaa aaaa
|
||||||
|
b . b . . c b c b c
|
||||||
|
b . b . . c b c b c
|
||||||
|
dddd dddd .... dddd dddd
|
||||||
|
. f e f . f e f . f
|
||||||
|
. f e f . f e f . f
|
||||||
|
gggg gggg .... gggg gggg
|
||||||
|
|
||||||
|
So, to render a 1, only segments c and f would be turned on; the rest would be off. To render a 7, only segments a, c, and f would be turned on.
|
||||||
|
|
||||||
|
The problem is that the signals which control the segments have been mixed up on each display. The submarine is still trying to display numbers by producing output on signal wires a through g, but those wires are connected to segments randomly. Worse, the wire/segment connections are mixed up separately for each four-digit display! (All of the digits within a display use the same connections, though.)
|
||||||
|
|
||||||
|
So, you might know that only signal wires b and g are turned on, but that doesn't mean segments b and g are turned on: the only digit that uses two segments is 1, so it must mean segments c and f are meant to be on. With just that information, you still can't tell which wire (b/g) goes to which segment (c/f). For that, you'll need to collect more information.
|
||||||
|
|
||||||
|
For each display, you watch the changing signals for a while, make a note of all ten unique signal patterns you see, and then write down a single four digit output value (your puzzle input). Using the signal patterns, you should be able to work out which pattern corresponds to which digit.
|
||||||
|
|
||||||
|
For example, here is what you might see in a single entry in your notes:
|
||||||
|
|
||||||
|
acedgfb cdfbe gcdfa fbcad dab cefabd cdfgeb eafb cagedb ab |
|
||||||
|
cdfeb fcadb cdfeb cdbaf
|
||||||
|
(The entry is wrapped here to two lines so it fits; in your notes, it will all be on a single line.)
|
||||||
|
|
||||||
|
Each entry consists of ten unique signal patterns, a | delimiter, and finally the four digit output value. Within an entry, the same wire/segment connections are used (but you don't know what the connections actually are). The unique signal patterns correspond to the ten different ways the submarine tries to render a digit using the current wire/segment connections. Because 7 is the only digit that uses three segments, dab in the above example means that to render a 7, signal lines d, a, and b are on. Because 4 is the only digit that uses four segments, eafb means that to render a 4, signal lines e, a, f, and b are on.
|
||||||
|
|
||||||
|
Using this information, you should be able to work out which combination of signal wires corresponds to each of the ten digits. Then, you can decode the four digit output value. Unfortunately, in the above example, all of the digits in the output value (cdfeb fcadb cdfeb cdbaf) use five segments and are more difficult to deduce.
|
||||||
|
|
||||||
|
For now, focus on the easy digits. Consider this larger example:
|
||||||
|
|
||||||
|
be cfbegad cbdgef fgaecd cgeb fdcge agebfd fecdb fabcd edb |
|
||||||
|
fdgacbe cefdb cefbgd gcbe
|
||||||
|
edbfga begcd cbg gc gcadebf fbgde acbgfd abcde gfcbed gfec |
|
||||||
|
fcgedb cgb dgebacf gc
|
||||||
|
fgaebd cg bdaec gdafb agbcfd gdcbef bgcad gfac gcb cdgabef |
|
||||||
|
cg cg fdcagb cbg
|
||||||
|
fbegcd cbd adcefb dageb afcb bc aefdc ecdab fgdeca fcdbega |
|
||||||
|
efabcd cedba gadfec cb
|
||||||
|
aecbfdg fbg gf bafeg dbefa fcge gcbea fcaegb dgceab fcbdga |
|
||||||
|
gecf egdcabf bgf bfgea
|
||||||
|
fgeab ca afcebg bdacfeg cfaedg gcfdb baec bfadeg bafgc acf |
|
||||||
|
gebdcfa ecba ca fadegcb
|
||||||
|
dbcfg fgd bdegcaf fgec aegbdf ecdfab fbedc dacgb gdcebf gf |
|
||||||
|
cefg dcbef fcge gbcadfe
|
||||||
|
bdfegc cbegaf gecbf dfcage bdacg ed bedf ced adcbefg gebcd |
|
||||||
|
ed bcgafe cdgba cbgef
|
||||||
|
egadfb cdbfeg cegd fecab cgb gbdefca cg fgcdab egfdb bfceg |
|
||||||
|
gbdfcae bgc cg cgb
|
||||||
|
gcafb gcf dcaebfg ecagb gf abcdeg gaef cafbge fdbac fegbdc |
|
||||||
|
fgae cfgab fg bagce
|
||||||
|
Because the digits 1, 4, 7, and 8 each use a unique number of segments, you should be able to tell which combinations of signals correspond to those digits. Counting only digits in the output values (the part after | on each line), in the above example, there are 26 instances of digits that use a unique number of segments (highlighted above).
|
||||||
|
|
||||||
|
In the output values, how many times do digits 1, 4, 7, or 8 appear?
|
||||||
|
|
||||||
|
--- Part Two ---
|
||||||
|
Through a little deduction, you should now be able to determine the remaining digits. Consider again the first example above:
|
||||||
|
|
||||||
|
acedgfb cdfbe gcdfa fbcad dab cefabd cdfgeb eafb cagedb ab |
|
||||||
|
cdfeb fcadb cdfeb cdbaf
|
||||||
|
After some careful analysis, the mapping between signal wires and segments only make sense in the following configuration:
|
||||||
|
|
||||||
|
dddd
|
||||||
|
e a
|
||||||
|
e a
|
||||||
|
ffff
|
||||||
|
g b
|
||||||
|
g b
|
||||||
|
cccc
|
||||||
|
So, the unique signal patterns would correspond to the following digits:
|
||||||
|
|
||||||
|
acedgfb: 8
|
||||||
|
cdfbe: 5
|
||||||
|
gcdfa: 2
|
||||||
|
fbcad: 3
|
||||||
|
dab: 7
|
||||||
|
cefabd: 9
|
||||||
|
cdfgeb: 6
|
||||||
|
eafb: 4
|
||||||
|
cagedb: 0
|
||||||
|
ab: 1
|
||||||
|
Then, the four digits of the output value can be decoded:
|
||||||
|
|
||||||
|
cdfeb: 5
|
||||||
|
fcadb: 3
|
||||||
|
cdfeb: 5
|
||||||
|
cdbaf: 3
|
||||||
|
Therefore, the output value for this entry is 5353.
|
||||||
|
|
||||||
|
Following this same process for each entry in the second, larger example above, the output value of each entry can be determined:
|
||||||
|
|
||||||
|
fdgacbe cefdb cefbgd gcbe: 8394
|
||||||
|
fcgedb cgb dgebacf gc: 9781
|
||||||
|
cg cg fdcagb cbg: 1197
|
||||||
|
efabcd cedba gadfec cb: 9361
|
||||||
|
gecf egdcabf bgf bfgea: 4873
|
||||||
|
gebdcfa ecba ca fadegcb: 8418
|
||||||
|
cefg dcbef fcge gbcadfe: 4548
|
||||||
|
ed bcgafe cdgba cbgef: 1625
|
||||||
|
gbdfcae bgc cg cgb: 8717
|
||||||
|
fgae cfgab fg bagce: 4315
|
||||||
|
Adding all of the output values in this larger example produces 61229.
|
||||||
|
|
||||||
|
For each entry, determine all of the wire/segment connections and decode the four-digit output values. What do you get if you add up all of the output values?
|
||||||
Loading…
Add table
Add a link
Reference in a new issue