Handle $ref defined types errors
We use $ref in the schema to allow us to specify multiple type, eg command, it can be a string or a list of strings. It required some extra parsing to retrieve a helpful type to display in our error message rather than 'string or string'. Which while correct, is not helpful. We value helpful. Signed-off-by: Mazz Mosley <mazz@houseofmnowster.com>
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2 changed files with 27 additions and 2 deletions
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@ -55,6 +55,16 @@ def process_errors(errors):
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def _clean_error_message(message):
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return message.replace("u'", "'")
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def _parse_valid_types_from_schema(schema):
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"""
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Our defined types using $ref in the schema require some extra parsing
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retrieve a helpful type for error message display.
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"""
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if '$ref' in schema:
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return schema['$ref'].replace("#/definitions/", "").replace("_", " ")
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else:
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return str(schema['type'])
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root_msgs = []
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invalid_keys = []
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required = []
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@ -93,9 +103,11 @@ def process_errors(errors):
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required.append(_clean_error_message(error.message))
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elif error.validator == 'oneOf':
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config_key = error.path[0]
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valid_types = [context.validator_value for context in error.context]
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valid_types = [_parse_valid_types_from_schema(schema) for schema in error.schema['oneOf']]
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valid_type_msg = " or ".join(valid_types)
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type_errors.append("Service '{}' configuration key '{}' contains an invalid type, it should be either {}".format(
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type_errors.append("Service '{}' configuration key '{}' contains an invalid type, valid types are {}".format(
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service_name, config_key, valid_type_msg)
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)
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elif error.validator == 'type':
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