Pick the first container
Rather than inefficiently looping through all the containers that a service has and overriding each volumes_from value, pick the first one and return that. Signed-off-by: Mazz Mosley <mazz@houseofmnowster.com>
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3 changed files with 6 additions and 5 deletions
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@ -994,8 +994,9 @@ def build_volume_from(volume_from_spec):
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containers = volume_from_spec.source.containers(stopped=True)
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if not containers:
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return ["{}:{}".format(volume_from_spec.source.create_container().id, volume_from_spec.mode)]
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else:
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return ["{}:{}".format(container.id, volume_from_spec.mode) for container in containers]
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container = containers[0]
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return ["{}:{}".format(container.id, volume_from_spec.mode)]
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elif isinstance(volume_from_spec.source, Container):
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return ["{}:{}".format(volume_from_spec.source.id, volume_from_spec.mode)]
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