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Always expose underlying type of enum

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This commit is contained in:
Jonathan Müller 2017-04-06 11:51:31 +02:00
commit 251e9abf5f
4 changed files with 30 additions and 25 deletions
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4
src/code_generator.cpp
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@ -205,10 +205,10 @@ namespace
if (e.is_scoped())
output << whitespace << keyword("class");
output << whitespace << identifier(e.name());
if (e.underlying_type())
if (e.has_explicit_type())
{
output << newl << punctuation(":");
detail::write_type(output, e.underlying_type().value(), "");
detail::write_type(output, e.underlying_type(), "");
}
if (e.is_definition())

9
src/libclang/enum_parser.cpp
View file

@ -53,12 +53,11 @@ namespace
detail::skip_attribute(stream);
auto& name = stream.get().value();
std::unique_ptr<cpp_type> type;
if (detail::skip_if(stream, ":"))
// parse type, explictly given one
type = detail::parse_type(context, cur, clang_getEnumDeclIntegerType(cur));
// parse type
auto type = detail::parse_type(context, cur, clang_getEnumDeclIntegerType(cur));
auto type_given = detail::skip_if(stream, ":");
return cpp_enum::builder(name.c_str(), scoped, std::move(type));
return cpp_enum::builder(name.c_str(), scoped, std::move(type), type_given);
}
}