BTree: restructured for memory layout efficiency
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1 changed files with 73 additions and 67 deletions
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@ -2,25 +2,26 @@
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# max children per B-tree node = M-1
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# max children per B-tree node = M-1
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# (must be even and greater than 2)
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# (must be even and greater than 2)
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const
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const
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M = 4
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M = 4
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Mhalf = M div 2
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Mhalf = M div 2
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type
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type
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Key = string
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Key = string
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Val = string
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Val = string
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Entry = ref object
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key: Key
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val: Val # external nodes only
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next: Node # internal nodes only; helper field to iterate over array entries
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Node = ref object
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Node = ref object
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m: int
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m: int
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children: array[M, Entry]
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keys: array[M, Key]
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case isInternal: bool
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of false:
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vals: array[M, Val]
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of true:
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links: array[M, Node]
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BTree = ref object
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BTree = ref object
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root: Node
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root: Node
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height: int ## height
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height: int ## height
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n: int ## number of key-value pairs
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n: int ## number of key-value pairs
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proc newBTree(): BTree = BTree(root: Node(m: 0))
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proc newBTree(): BTree = BTree(root: Node(m: 0, isInternal: false))
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proc less(a, b: Key): bool = cmp(a, b) < 0
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proc less(a, b: Key): bool = cmp(a, b) < 0
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@ -28,63 +29,61 @@ proc eq(a, b: Key): bool = cmp(a, b) == 0
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proc search(x: Node, key: Key, ht: int): Val =
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proc search(x: Node, key: Key, ht: int): Val =
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if ht == 0:
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if ht == 0:
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# external node
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assert(not x.isInternal)
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for j in 0 ..< x.m:
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for j in 0 ..< x.m:
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if eq(key, x.children[j].key): return x.children[j].val
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if eq(key, x.keys[j]): return x.vals[j]
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else:
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else:
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# internal node
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assert(x.isInternal)
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for j in 0 ..< x.m:
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for j in 0 ..< x.m:
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if j+1 == x.m or less(key, x.children[j+1].key):
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if j+1 == x.m or less(key, x.keys[j+1]):
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return search(x.children[j].next, key, ht-1)
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return search(x.links[j], key, ht-1)
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return nil
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proc candidates(x: Node, key: Key, ht: int): Node =
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if ht == 0:
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return x
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else:
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# internal node
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for j in 0 ..< x.m:
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if j+1 == x.m or less(key, x.children[j+1].key):
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return candidates(x.children[j].next, key, ht-1)
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return nil
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iterator allValues(t: BTree; key: Key): Val =
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let x = candidates(t.root, key, t.height)
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if x != nil:
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for j in 0 ..< x.m:
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if eq(key, x.children[j].key): yield x.children[j].val
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proc get(t: BTree; key: Key): Val = search(t.root, key, t.height)
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proc get(t: BTree; key: Key): Val = search(t.root, key, t.height)
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proc split(h: Node): Node =
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proc split(h: Node): Node =
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## split node in half
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## split node in half
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result = Node(m: Mhalf)
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result = Node(m: Mhalf, isInternal: h.isInternal)
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h.m = Mhalf
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h.m = Mhalf
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for j in 0 ..< Mhalf:
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for j in 0 ..< Mhalf:
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result.children[j] = h.children[Mhalf + j]
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result.keys[j] = h.keys[Mhalf + j]
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if h.isInternal:
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for j in 0 ..< Mhalf:
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result.links[j] = h.links[Mhalf + j]
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else:
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for j in 0 ..< Mhalf:
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shallowCopy(result.vals[j], h.vals[Mhalf + j])
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proc insert(h: Node, key: Key, val: Val, ht: int): Node =
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proc insert(h: Node, key: Key, val: Val, ht: int): Node =
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var t = Entry(key: key, val: val, next: nil)
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#var t = Entry(key: key, val: val, next: nil)
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var newKey = key
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var j = 0
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var j = 0
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if ht == 0:
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if ht == 0:
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# external node:
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assert(not h.isInternal)
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while j < h.m:
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while j < h.m:
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if less(key, h.children[j].key): break
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if less(key, h.keys[j]): break
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inc j
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inc j
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for i in countdown(h.m, j+1):
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shallowCopy(h.vals[i], h.vals[i-1])
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h.vals[j] = val
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else:
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else:
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# internal node
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assert h.isInternal
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var newLink: Node = nil
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while j < h.m:
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while j < h.m:
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if j+1 == h.m or less(key, h.children[j+1].key):
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if j+1 == h.m or less(key, h.keys[j+1]):
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let u = insert(h.children[j].next, key, val, ht-1)
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let u = insert(h.links[j], key, val, ht-1)
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inc j
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inc j
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if u == nil: return nil
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if u == nil: return nil
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t.key = u.children[0].key
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newKey = u.keys[0]
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t.next = u
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newLink = u
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break
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break
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inc j
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inc j
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for i in countdown(h.m, j+1):
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h.links[i] = h.links[i-1]
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h.links[j] = newLink
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for i in countdown(h.m, j+1):
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for i in countdown(h.m, j+1):
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h.children[i] = h.children[i-1]
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h.keys[i] = h.keys[i-1]
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h.children[j] = t
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h.keys[j] = newKey
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inc h.m
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inc h.m
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return if h.m < M: nil else: split(h)
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return if h.m < M: nil else: split(h)
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@ -94,21 +93,25 @@ proc put(b: BTree; key: Key; val: Val) =
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if u == nil: return
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if u == nil: return
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# need to split root
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# need to split root
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let t = Node(m: 2)
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let t = Node(m: 2, isInternal: true)
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t.children[0] = Entry(key: b.root.children[0].key, val: nil, next: b.root)
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t.keys[0] = b.root.keys[0]
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t.children[1] = Entry(key: u.children[0].key, val: nil, next: u)
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t.links[0] = b.root
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t.keys[1] = u.keys[0]
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t.links[1] = u
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b.root = t
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b.root = t
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inc b.height
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inc b.height
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proc toString(h: Node, ht: int, indent: string; result: var string) =
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proc toString(h: Node, ht: int, indent: string; result: var string) =
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if ht == 0:
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if ht == 0:
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assert(not h.isInternal)
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for j in 0..<h.m:
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for j in 0..<h.m:
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result.add(indent)
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result.add(indent)
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result.add($h.children[j].key & " " & $h.children[j].val & "\n")
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result.add($h.keys[j] & " " & $h.vals[j] & "\n")
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else:
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else:
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assert(h.isInternal)
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for j in 0..<h.m:
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for j in 0..<h.m:
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if j > 0: result.add(indent & "(" & $h.children[j].key & ")\n")
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if j > 0: result.add(indent & "(" & $h.keys[j] & ")\n")
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toString(h.children[j].next, ht-1, indent & " ", result)
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toString(h.links[j], ht-1, indent & " ", result)
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proc `$`(b: BTree): string =
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proc `$`(b: BTree): string =
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result = ""
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result = ""
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@ -116,8 +119,8 @@ proc `$`(b: BTree): string =
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proc main =
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proc main =
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var st = newBTree()
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var st = newBTree()
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st.put("www.cs.princeton.edu", "128.112.136.12")
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st.put("www.cs.princeton.edu", "abc")
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st.put("www.cs.princeton.edu", "128.112.136.11")
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st.put("www.cs.princeton.edu", "xyz")
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st.put("www.princeton.edu", "128.112.128.15")
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st.put("www.princeton.edu", "128.112.128.15")
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st.put("www.yale.edu", "130.132.143.21")
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st.put("www.yale.edu", "130.132.143.21")
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st.put("www.simpsons.com", "209.052.165.60")
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st.put("www.simpsons.com", "209.052.165.60")
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@ -134,23 +137,26 @@ proc main =
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st.put("www.weather.com", "63.111.66.11")
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st.put("www.weather.com", "63.111.66.11")
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st.put("www.yahoo.com", "216.109.118.65")
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st.put("www.yahoo.com", "216.109.118.65")
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echo("cs.princeton.edu: ", st.get("www.cs.princeton.edu"))
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assert st.get("www.cs.princeton.edu") == "abc"
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echo("hardvardsucks.com: ", st.get("www.harvardsucks.com"))
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assert st.get("www.harvardsucks.com") == nil
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echo("simpsons.com: ", st.get("www.simpsons.com"))
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echo("apple.com: ", st.get("www.apple.com"))
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echo("ebay.com: ", st.get("www.ebay.com"))
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echo("dell.com: ", st.get("www.dell.com"))
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echo()
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echo("size: ", st.n)
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echo("height: ", st.height)
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echo(st)
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var dups = newBTree()
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assert st.get("www.simpsons.com") == "209.052.165.60"
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for i in 0..20:
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assert st.get("www.apple.com") == "17.112.152.32"
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dups.put("testme", $i)
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assert st.get("www.ebay.com") == "66.135.192.87"
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echo dups
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assert st.get("www.dell.com") == "143.166.224.230"
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for v in allValues(dups, "testme"):
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assert(st.n == 17)
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echo v
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assert(st.height == 2)
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echo dups.get("testme")
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when true:
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var b2 = newBTree()
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const iters = 10_000
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for i in 1..iters:
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b2.put($i, $(iters - i))
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for i in 1..iters:
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let x = b2.get($i)
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if x != $(iters - i):
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echo "got ", x, ", but expected ", iters - i
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echo b2.n
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echo b2.height
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main()
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main()
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