Do not use "make -s" in the CI builds

We want to have as much information as possible in case of the build
failure, so don't use the "--silent" make option.

.github/workflows/ci.yml

@@ -97,12 +97,12 @@ jobs:
       working-directory: build/build
       run: |
           set -x
-          make -s $SWIGJOBS
+          make $SWIGJOBS
           ./swig -version && ./swig -pcreversion
-          if test -z "$SWIGLANG"; then make -s $SWIGJOBS check-ccache; fi
-          if test -z "$SWIGLANG"; then make -s $SWIGJOBS check-errors-test-suite; fi
+          if test -z "$SWIGLANG"; then make $SWIGJOBS check-ccache; fi
+          if test -z "$SWIGLANG"; then make $SWIGJOBS check-errors-test-suite; fi
           echo 'Installing...'
-          if test -z "$SWIGLANG"; then sudo make -s install && swig -version && ccache-swig -V; fi
+          if test -z "$SWIGLANG"; then sudo make install && swig -version && ccache-swig -V; fi
 
     - name: Test
       working-directory: build/build
@@ -114,7 +114,7 @@ jobs:
           # Stricter compile flags for examples. Various headers and SWIG generated code prevents full use of -pedantic.
           if test -n "$SWIGLANG"; then cflags=$($GITHUB_WORKSPACE/Tools/testflags.py --language $SWIGLANG --cflags --std=$CSTD --compiler=$CC) && echo $cflags; fi
           if test -n "$SWIGLANG"; then cxxflags=$($GITHUB_WORKSPACE/Tools/testflags.py --language $SWIGLANG --cxxflags --std=$CPPSTD --compiler=$CC) && echo $cxxflags; fi
-          if test -n "$SWIGLANG"; then make -s check-$SWIGLANG-version; fi
+          if test -n "$SWIGLANG"; then make check-$SWIGLANG-version; fi
           if test -n "$SWIGLANG"; then make check-$SWIGLANG-enabled; fi
           if test -n "$SWIGLANG"; then make $SWIGJOBS check-$SWIGLANG-examples CFLAGS="$cflags" CXXFLAGS="$cxxflags"; fi
           if test -n "$SWIGLANG"; then make $SWIGJOBS check-$SWIGLANG-test-suite CFLAGS="$cflags" CXXFLAGS="$cxxflags"; fi