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Allow an instantiated template to have the same name as the C++ template name

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For example, this is now possible:
  template<typename T> struct X { ... };
  %template(X) X<int>;
Closes #1100.
This commit is contained in:
William S Fulton 2017-09-29 21:18:57 +01:00
commit e27a606335
7 changed files with 325 additions and 4 deletions
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51
Examples/test-suite/errors/cpp_template_duplicate_names.i Normal file
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%module cpp_template_duplicate_names
// From test-suite/template_class_reuse.i test
%{
namespace Space {
template <bool B> struct Duplicate1 { void f(){}; };
}
%}
// %warnfilter(SWIGWARN_PARSE_REDEFINED) Space::Duplicate1;
namespace Space {
template <bool B> struct Duplicate1 { void f(){}; };
template <bool B> struct Duplicate1 { void f(){}; };
}
// %warnfilter(SWIGWARN_PARSE_REDEFINED) Space::Duplicate2;
%inline %{
namespace Space {
template <int I> struct Duplicate2 { void n(){}; };
}
%}
%template(Duplicate2_0) Space::Duplicate2<0>;
%template(Duplicate2_0) Space::Duplicate2<0>;
// %warnfilter(SWIGWARN_PARSE_REDEFINED) Space::Duplicate3;
%inline %{
namespace Space {
template <int I> struct Duplicate3 { void n(){}; };
}
%}
%template(Duplicate3) Space::Duplicate3<0>;
%template(Duplicate3) Space::Duplicate3<0>;
%{
namespace Space {
template <bool B> struct Duplicate4 { void f(){}; };
}
%}
// %warnfilter(SWIGWARN_PARSE_REDEFINED) Space::Duplicate4;
namespace Space {
template <bool B> struct Duplicate4 { void f(){}; };
template <bool B> struct Duplicate4 { void f(){}; };
}
%template(Duplicate4) Space::Duplicate4<0>;
%template(Duplicate4) Space::Duplicate4<0>;