e1afb6fdbe
Problem: When enum value contains compound expression with a char
constant, the quotes around char constant is missing in the generated
expression. Example:
enum media_type {
YUY2 = ((('2' << 24) | ('Y' << 16)) | ('U' << 8)) | 'Y'
};
The generated C# enum becomes:
public enum media_type {
YUY2 = (((2 << 24)|(Y << 16))|(U << 8))|Y
}
While the correct representation (after this fix) should be:
public enum media_type {
YUY2 = ((('2' << 24)|('Y' << 16))|('U' << 8))|'Y'
}
Causes: the exprcompound promotes the expression type from char to int
and uses $1.val in the generated expression. However $1.val does not
contain the quotes. Since the type is promoted to int, there's no way to
know there's char component in the compound expression.
Solution: in exprcomound, use $1.rawval if $1.type is T_CHAR or T_WCHAR.
The rawval contains quotes which yield correct expression.
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| .. | ||
| cparse.h | ||
| cscanner.c | ||
| parser.y | ||
| templ.c | ||
| util.c | ||