Don't create a new buffer when opening the vimspector tab
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parent
03d97dc58f
commit
8664c0ad78
2 changed files with 2 additions and 10 deletions
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@ -22,7 +22,7 @@ from vimspector import utils
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class CodeView( object ):
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def __init__( self, window, original_window, api_prefix ):
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def __init__( self, window, api_prefix ):
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self._window = window
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self._api_prefix = api_prefix
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@ -42,7 +42,6 @@ class CodeView( object ):
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with utils.LetCurrentWindow( self._window ):
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vim.current.buffer = original_window.buffer
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vim.command( 'nnoremenu WinBar.Continue :call vimspector#Continue()<CR>' )
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vim.command( 'nnoremenu WinBar.Next :call vimspector#StepOver()<CR>' )
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vim.command( 'nnoremenu WinBar.Step :call vimspector#StepInto()<CR>' )
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@ -150,10 +150,6 @@ class DebugSession( object ):
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adapter = adapter_dict
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# TODO: Do we want some form of persistence ? e.g. self._staticVariables,
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# set from an api call like SetLaunchParam( 'var', 'value' ), perhaps also a
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# way to load .vimspector.local.json which just sets variables
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#
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# Additional vars as defined by VSCode:
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#
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# ${workspaceFolder} - the path of the folder opened in VS Code
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@ -457,14 +453,11 @@ class DebugSession( object ):
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def _SetUpUI( self ):
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original_window = vim.current.window
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vim.command( 'tabnew' )
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vim.command( 'tabedit %' )
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self._uiTab = vim.current.tabpage
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# Code window
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self._codeView = code.CodeView( vim.current.window,
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original_window,
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self._api_prefix )
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# Call stack
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